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添加截取url是否带参数的判断

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xuwenbo
2020-09-14 10:44:03 +08:00
parent 79930429d8
commit bd82399ff1
1 changed files with 7 additions and 6 deletions
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13
utils/index.js
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@ -681,13 +681,14 @@ export function handleQrCode() {
export function handleUrlParam(path) { export function handleUrlParam(path) {
console.log(path) console.log(path)
var url = path.split("?")[1]; //获取url中"?"符后的字串
console.log(url)
var theRequest = new Object(); var theRequest = new Object();
let strs = url.split("&"); if(path.includes("?")){
for (var i = 0; i < strs.length; i++) { var url = path.split("?")[1]; //获取url中"?"符后的字串
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]); console.log(url)
let strs = url.split("&");
for (var i = 0; i < strs.length; i++) {
theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
}
} }
return theRequest; return theRequest;
} }